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Tag! I need you point me in the right direction here. where to focus my attention first. thank you in advance for your help! The graph of the equation is reflected over the and translated three units to the right to become g(x)gas depicted below. What is the equation for the graph of Für alle, die mir helfen möchten (automatisch von OnlineMathe generiert): "Ich möchte die Lösung in Zusammenarbeit mit anderen erstellen." |
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Hi, to reflect on the x-axis you just multiply by . Thus the reflected function is To shift to the right you subtract from the -variable: greetings, pivot |
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www.wolframalpha.com/input/?i=plot+-2x+%2C+-2%28x-3%29 |
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thank you both. I have not forgotten about the question. am just studying the topic. it is kind of new to me. I study math on my own and with textbooks. Don't go to school. I work. So I am sort of pressed for time. Thank you for the tips. I am studying everything about graph transformation and all that. I will get back if in doubt. |
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Tag, if didn't reply was because was studying the topic. it is a new one for me input all the equations given in the answer choice and was clear for me to see that choice the first one) was the right equation. Now, I would like to know how to do it without the graphing calculator. pivot, can you explain the reasoning behind what you wrote. I do not understand it well. thank you so much. |
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Let´s say the linear function is . Now you reflect it at the x-axis. For this purpose you just multiply the function by : . If then the function is translated units to the right you subtract from : If then the function is translated units to the left you add to : numerical example: Reflecting f(x) at the x-axis and then translate the reflected function two units to the left. , |
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thank you so much. Ich verstehe jetzt. I have also been watching some tutorials and videos about graphing transformation of exponential equations. |
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Freut mich, dass das klar ist. Transformationen von Exponentialfunktionen sind natürlich was anderes. If something unclear about that issue, feel free to ask a new question. |